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The legs if an isosceles triangle are (3x^2+4x+2) inches and the base is (4x-5) inches. Find the perimeter of the triangle

Respuesta :

calculista

Answer:

[tex]P=(6x^2+12x-1)\ in[/tex]

Step-by-step explanation:

we know that

An isosceles triangle has two equal sides and two equal angles

so

The perimeter of triangle is equal to

[tex]P=2(3x^2+4x+2)+(4x-5)[/tex]

Eliminate parenthesis

[tex]P=6x^2+8x+4+4x-5[/tex]

Combine like terms

[tex]P=(6x^2+12x-1)\ in[/tex]

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