Answer:
a
The volume of the aluminum is [tex]V = 9.25*10^{-5}m^3}[/tex]
b
The buoyant force exerted is [tex]F_B =0.9N[/tex]
From the question we are told that
The mass of the aluminum is [tex]M_A = 0.25Kg[/tex]
The density of the aluminum is [tex]\rho_A = 2700 kg/m^3[/tex]
Generally volume is mathematically represented as
[tex]V = \frac{M_A}{\rho_A}[/tex]
Substituting values accordingly
[tex]V =\frac{0.25}{2700} =9.25*10^{-5}m^3[/tex]
Generally buoyant force is mathematically represented as
[tex]F_B = V \rho_wg[/tex]
Where V is the volume of the aluminum [tex]=9.25*10^{-5}m^3[/tex]
[tex]\rho_w[/tex] is the density of water [tex]=1000kg/m^3[/tex]
g is the acceleration due to gravity = [tex]=9.8m/s^2[/tex]
Substituting these values accordingly we have
[tex]F_B = 9.25*10^{-5} * 1000 * 9.8[/tex]
[tex]=0.9N[/tex]
