Answer:
The solutions are x=-11 and x=5
Step-by-step explanation:
we have
[tex](x+3)^2+8=72[/tex]
Is a quadratic equation or equation of second degree.
The degree (largest exponent) is 2 so the maximum number of roots (solutions) is 2
Solve for x
[tex](x+3)^2=72-8[/tex]
[tex](x+3)^2=64[/tex]
take square root both sides
[tex]x+3=\pm8[/tex]
subtract 3 both sides
[tex]x=-3\pm8[/tex]
[tex]x=-3+8=5[/tex]
[tex]x=-3-8=-11[/tex]
therefore
The solutions are x=-11 and x=5
