Answer:
The the factors of [tex]x^2-4x-5[/tex] are (x+1) and (x-5)
Step-by-step explanation:
Considering the expression
[tex]x^2-4x-5[/tex]
[tex]\mathrm{Break\:the\:expression\:into\:groups}[/tex]
[tex]=\left(x^2+x\right)+\left(-5x-5\right)[/tex]
[tex]\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2+x\mathrm{:\quad }x\left(x+1\right)[/tex]
[tex]\mathrm{Factor\:out\:}-5\mathrm{\:from\:}-5x-5\mathrm{:\quad }-5\left(x+1\right)[/tex]
[tex]=x\left(x+1\right)-5\left(x+1\right)[/tex]
[tex]\mathrm{Factor\:out\:common\:term\:}x+1[/tex]
[tex]=\left(x+1\right)\left(x-5\right)[/tex]
Therefore, the the factors of [tex]x^2-4x-5[/tex] are (x+1) and (x-5)
