Answer:
49101
Step-by-step explanation:
-We notice that this is an exponential growth problem.
-Exponential growth is expressed as:
[tex]A_t=A_oe^{kt},\\\\A_t-pop \ at\ t\\A_o-Intial \ pop\\k-growth \ constant\\t-time[/tex]
Let X be the initial population growing at 9%, Given the initial time as 2010 and the final time as 2018, our population is estimated as:
[tex]A_t=23900^{(2018-2010)K}\\\\=23900e^{8\times 0.09}\\\\=49100.95\approx49101[/tex]
Hence, the fox population is estimated to be 49,101 in 2018
