Answer:
plane a because it was 10.46 miles away
Step-by-step explanation:
We use the Sine Rule to determine which plane is further away after 7 miles off the ground.
#Plane A departs at 42°, The 7 mile flight corresponds to the 42°:
[tex]\frac{a}{Sin \ A}=\frac{b}{Sin \ B}\\\\\frac{7}{Sin \ 42\textdegree}=\frac{a}{Sin \ 90\textdegree}\\\\a=7\ Sin \ 42\textdegree\\\\=10.46\ miles[/tex]
#Plane B departs at 44°,The 7 mile flight corresponds to the 42°:
[tex]\frac{a}{Sin \ A}=\frac{b}{Sin \ B}\\\\\frac{7}{Sin \ 44\textdegree}=\frac{b}{Sin \ 90\textdegree}\\\\b=7\ Sin \ 44\textdegree\\\\=10.08\ miles[/tex]
Hence, Plane A since it's 10.46 miles away.
