An isosceles triangle has a perimeter of 36 inches. Its base is 2
1
2
times longer than each of its legs. What are the lengths of the sides of the triangle?

Respuesta :

The lengths of the sides of the triangle are 8, 8, 20

Explanation:

Given that the perimeter of an isosceles triangle is 36 inches.

The base of the triangle is [tex]2\frac{1}{2}[/tex] times longer than each of its legs.

We need to determine the lengths of the sides of the triangle.

Lengths of the sides:

Let x denote the lengths of the sides of the triangle.

The base of the triangle is given by

[tex]2\frac{1}{2}x=\frac{5}{2}x=2.5x[/tex]

Perimeter of the isosceles triangle = Sum of the three sides of the triangle.

Thus, we have,

[tex]36=x+x+2.5x[/tex]

[tex]36=4.5x[/tex]

[tex]8=x[/tex]

Thus, the length of the sides of the isosceles triangle is 8 inches.

Base of the triangle = [tex]2.5(8)=20 \ inches[/tex]

Hence, the three sides of the isosceles triangle are 8, 8, 20