Answer:
The biking part of the triathlon is 11.70 miles away.
Step-by-step explanation:
From the right angle Δ ABC
[tex]AC^{2} = AB^{2} + BC^{2}[/tex]
Since AB = 4 mile
& BC = 11 miles
⇒ [tex]AC^{2} = 11^{2} + 4^{2}[/tex]
⇒ [tex]AC^{2}[/tex] = 121 + 16
⇒ [tex]AC^{2}[/tex] = 137
⇒ AC = [tex]\sqrt{137}[/tex]
⇒ AC = 11.70 miles
Thus the biking part of the triathlon is 11.70 miles away.
