Answer:
A. 181.24 N
Explanation:
The magnitude of hte electrostatic force between two charged objects is given by the equation
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where
k is the Coulomb's constant
q1, q2 are the magnitudes of the two charges
r is the separation between the charges
In this problem, we have:
[tex]q_1=4.5\mu C=4.5\cdot 10^{-6}C[/tex] is the magnitude of the 1st charge
[tex]q_2=2.8\mu C=2.8\cdot 10^{-6}C[/tex] is the magnitude of the 2nd charge
r = 2.5 cm = 0.025 m is the separation between the charges
Therefore, the magnitude of the electric force is:
[tex]F=\frac{(9\cdot 10^9)(4.5\cdot 10^{-6})(2.8\cdot 10^{-6})}{(0.025)^2}=181.44 N[/tex]
So, the closest answer is
A) 181.24 N
