Answer:
The only parameter that changes is mass m
It is only necessary to calculate the ratio Eh/Ee
[tex]m_{h}=3m_{e}\\E_{h}=\frac{3m_{e}v^{2}}{2}\\E_{e}=\frac{m_{e}v^{2}}{2}\\\frac{E{h}}{E{e}}=3[/tex]
The kinetic energy of the heavy paricle is three times the kinetic energy of an electron