An electron de-excites from the fourth quantum level to the third and then directly to the first. Two frequencies of light are emitted. How do their combined energies compare to the energy of the single frequency that would be emitted by de-excitation from the fourth level directly to the first level?

The energy emitted during the de-excitation of an electron from a higher energy level to a lower energy level is directly proportional to the frequency of the emitted light.

Here, the total sum of the energies of 2 frequencies of light emitted in different stages is equal to the energy of a single frequency of light during the de-excitation of fourth level to ground level directly.

Hence the total sum of of the frequencies of 2 lights emitted in different stages is equal to the frequency of single frequency of light emitted during the de-excitation from fourth level to ground level directly.

The some of the energies of 2 frequencies emitted by one electron is equal to the energy of a single frequency when electron jumps directly.

JackelineCasarez JackelineCasarez · Answer 2 · 2021-12-05T16:07:29+01:00

The way in which the amalgamated energies of the two given frequencies are released through de-excitation from fourth to first level directly would be:

- equal to the energy of the single frequency.

'De-excitation' is described as the process in which there is an alteration in the state of excitement of electrons due to the liberation of quantum of energy.
In the given situation, the de-excitement takes place from level four to level three and to level one later which causes the release/liberation of quantum energy.
Thus, the totality of the energies given by both the frequencies would be equal to the energy given by individual frequency.

two frequencies emitted by the one electrons is

Learn more about 'Quantum' here:

brainly.com/question/16977590