contestada

1. A0_50 kg football is thrown with a velocity of 15 m/s to the right. A sta-
tionary rocciver catches the ball and brings it to rest in 0.020 s. What is
the force exerted on the receiver?

Respuesta :

olatunbosunadeoke

Answer: 375 Newton

Explanation:

Initial velocity = 15 m/s

Final velocity = 0 m/s

Mass of football = 0.50kg

Time taken = 0.020Seconds

Force = (Change in momentum / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum = 0.50 x (0 - 15)

= 0.50 (-15)

= - 7.5kgm/s

Then, put - 7.5kgm/s in the equation of force

i.e Force = (Change in momentum / Time taken)

Force = (- 7.5kgm/s / 0.020 Seconds)

Force = 375 Newton (note that the negative sign does not affect the value of force)

Thus, 375 Newton of force was exerted on the receiver

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