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The voltage across a 5-μF capacitor is known to be vc = 125t e^(−1000t) V for t ≥ 0.
(a) Find the current through the capacitor for t > 0. Assume the passive sign convention.
(b) Find the power at the terminals of the capacitor when t = 15 μs.
(c) Is the capacitor absorbing or delivering power at t = 15 μs?
(d) Find the energy stored in the capacitor at t = 15μs.

Respuesta :

Answer:

a) i(t)=2.5*(e^(-2500*t))*(1-2500*t) mA

b) P=16.7 μW

c) the capacitor is absorbing power.

d) E = 1.29x10^-10 nJ

Explanation:

In this exercise we will use the concepts and formulas of electric current. The step-by-step solution is seen in the attached image.

Ver imagen lcoley8

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