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An electric device, which heats water by immersing a resistance wire in the water, generates 50 cal of heat per second when an electric potential difference of 12 V is placed across its leads. What is the resistance of the heater wire? (Note: 1 cal = 4.186 J)

Respuesta :

Answer:

0.69 ohm

Explanation:

Heat generated per second, H = 50 cal/s

Potential difference, V = 12 V

Let R is the resistance of coil.

The formula for the heat is given by

[tex]H = \frac{V^{2}}{R}t[/tex]

[tex]50\times 4.186 = \frac{12^{2}}{R}\times 1[/tex]

R = 0.69 ohm

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