Answer:
The number of atoms is [tex]N = 4.37*10^{22} \ atoms[/tex]
Explanation:
From the question we are told that
The mass of coin is [tex]m_n = 4.2g[/tex]
Number of atom in one mole = [tex]n =6.02*10^{23} \ atoms[/tex]
Molar mass of nickel [tex]M = 57.8g[/tex]
Now the relation to obtain the number of atom in the nickel coin is
[tex]N = \frac{Mass \ of Nickel\ coin}{Molar \ mass\ of nickel } * No\ of\atoms \ in \ \ one\ mole\ of\ nickel[/tex]
[tex]= \frac{4.2}{57.8}* 6.02*10^{23}[/tex]
[tex]=4.37 *10^{22} atoms[/tex]
