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The distance from city A to city B is approximately 2070 miles. A plane flying directly to city B passes over city A at noon. If the plane travels at 400 ​mph, find the rule of the function​ f(t) that gives the distance of the plane from city B at time t hours​ (with tequals0 corresponding to​ noon).

Respuesta :

Answer:

[tex]f(t) = -400t+2070[/tex]

Step-by-step explanation:

According to the information of the problem the plane is traveling at a constant velocity therefore the function that models that gives the distance of the plane from city B at time t hours would be linear. Something like this.

[tex]f(t) = mt+b[/tex]

The velocity is the slope of the line and if you take B as your reference you would be going backwards therefore we would say that   [tex]m = -400[/tex] . And as I mentioned before if you take B  as your reference your starting point would be 2070 miles away, therefore the function would be

[tex]f(t) = -400t+2070[/tex]

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