Answer:
Explanation:
Let the mass is m.
initial velocity, u = 10.6 mph
final velocity, v = 23.6 mph
initial kinetic energy, K = 0.5 mu²
K = 0.5 m x 10.6 x 10.6 = 56.18 m .... (1)
Final kinetic energy, K' = 0.5 mv²
K' = 0.5 x m x 23.6 x 23.6 = 278.48 m ..... (2)
Percentage increase in kinetic energy is given by
[tex]\frac{K'-K}{K}\times 100 = \frac{278.48 - 56.18}{56.18}\times 100 = 395.6 %[/tex]
So, it becomes four times.
