Respuesta :
The given question is incomplete. The complete question is ;
Ammonia gas can be prepared by the following reaction:
[tex]CaO(s)+2NH_4Cl(s)\rightarrow 2NH_3(g)+H_2O(g)+CaCl_2(s)[/tex]
In an experiment, 27.6 g of ammonia gas, [tex]NH_3[/tex], is produced when it was predicted that 50.2 g of [tex]NH_3[/tex] would form.
What is the theoretical yield of [tex]NH_3[/tex]? What is the actual yeild of [tex]NH_3[/tex]? What is the percent yeild of [tex]NH_3[/tex]?
Answer: a) 50.2 g
b) 27.6 g
c) 5.0 %
Explanation:
a) Theoretical yield is defined as the amount of the product that is possible in the reaction.
Theoretical yield of [tex]NH_3[/tex] = 50.2 g
b) Experimental or actual yield is defined as the amount of the product that is actually formed in the reaction.
Experimental yield of [tex]NH_3[/tex] = 27.6 g
c) Percentage yield is defined as the ratio of experimental yileld to the theoretical yield in terms of percentage.
[tex]{\text {percentage yield}}=\frac{\text {Experimental yield}}{\text {Theoretical yield}}\times 100\%[/tex]
[tex]{\text {percentage yield}}=\frac{27.6g}{50.2g}\times 100\%=55.0\%[/tex]
Hence percentage yield for the reaction is 55.0 %.
