Respuesta :
x = {0, π/6}
Step-by-step explanation:
2sin^2x-sinx=0
and i know the answer is this..
2sin²(x) - sin(x) = 0
sin2(x) is sin(x) × sin(x) so 2sin²(x) - sin(x) = 2 sin(x) × sin(x) - sin(x) and this expression has a common factor of sin(x) so
2sin²(x) - sin(x) = 2 sin(x) × sin(x) - sin(x) = sin(x) [2 sin(x) - 1]
sin(x)(2sin(x)-1) = 0
sin(x) = 0
x = 0
2sin(x) - 1 = 0
sin(x) = 1/2
x = π/6
x = {0, π/6}
The exact solutions are: [tex]x=0,\frac{\pi}{6},\frac{5\pi}{6},\pi,2\pi[/tex]
[tex]2\sin^{2}x-\sin x=0\\\sin x(2\sin x-1)=0[/tex]
Using zero product rule:
[tex]\sin x=0\\x=0,\pi,2\pi[/tex]
[tex]2\sin x-1=0\\\sin x=\frac{1}{2}\\x=\frac{\pi}{6},\frac{5\pi}{6}[/tex]
Learn more: https://brainly.com/question/16236436