Respuesta :
Answer: P(x > - 0.23) = 0.41
Step-by-step explanation:
Since we are assuming that the readings at freezing on a batch of thermometers are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the readings at freezing on a batch of thermometers.
µ = mean temperature reading
σ = standard deviation
From the information given,
µ = 0°C
σ = 1.00°C
the probability of obtaining a reading less than -0.23°C is expressed as
P(x > - 0.23)
For x = - 0.23
z = (- 0.23 - 0)/1 = - 0.23
Looking at the normal distribution table, the probability corresponding to the z score is 0.41
The probability of obtaining a reading less than -0.23°C is 0.41.
Calculation of the probability:
Since normally distributed with a mean of 0°C and a standard deviation of 1.00°C
So,
Here the following formula should be used.
[tex]z = (x - \mu)\div \sigma[/tex]
here
x = the readings at freezing
µ = mean = 0°C
σ = standard deviation = 1.00°C
So, the probability is
z = [tex](- 0.23 - 0)\div 1[/tex] = - 0.23
So look at the normal distribution table, the probability should be 0.41
Learn more about probability here: https://brainly.com/question/24299008
