contestada

find the coefficient of kinetic friction for a 10 kg box being dragged steadily across the surface with a force of 2.0 Newtons​

Respuesta :

Answer:

0.02

Explanation:

Force, [tex]F=\mu_k N[/tex] where N is normal reaction and coefficient of kinetic friction is [tex]\mu_k[/tex]. Also, N is equivalent to mg ie N=mg where m is mass of an object and g is acceleration due to gravity. Making [tex]\mu[/tex]the subject of the formula then

[tex]\mu_k=\frac {F}{mg}[/tex]

Substituting F with 2 N, m with 10 kg and g with 9.81 then

[tex]\mu_k=\frac {2}{10\times 9.81}=0.0203873598369\approx 0.02[/tex]