Answer:
It took the rock 2 seconds to get to the water from the bridge.
Explanation:
Since Forrest drops the rock, it means its initial velocity is zero, and because it is freely falling under the influence of gravity, after time [tex]t[/tex] it will gain a velocity [tex]v[/tex] of
[tex]v = gt[/tex],
solving for [tex]t[/tex] we get:
[tex]t = \dfrac{v}{g}.[/tex]
Since in our case the velocity the rock gained was [tex]v= 19.6m/s[/tex] and the acceleration due to gravity is [tex]g =9.8m/s^2[/tex], we have
[tex]t = \dfrac{19.6m/s}{9.8ms^{-2}}[/tex]
[tex]\boxed{t =2s.}[/tex]
Thus, the time took the rock to reach the water from the bridge was 2 seconds.
