A merry-go-round spins freely when Janice moves quickly to the center along a radius of the
merry-go-round. It is true to say that
A) the moment of inertia of the system decreases and the angular speed increases.
B) the moment of inertia of the system decreases and the angular speed decreases.
C) the moment of inertia of the system decreases and the angular speed remains the same.
D) the moment of inertia of the system increases and the angular speed increases.
E) the moment of inertia of the system increases and the angular speed decreases

Question

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Respuesta :

akindelemf akindelemf · Answer 1 · 2020-03-25T15:21:00+01:00

Answer:

Option A - the moment of inertia of the system decreases and the angular speed increases.

Explanation:

The moment of Inertia of merry- go-round spins is

I = [tex]I_{cm}[/tex]+ mr²

ζ = I[tex]\alpha[/tex]

ζ =( [tex]I_{cm}[/tex]+ mr²) [tex]\alpha[/tex]

[tex]\alpha[/tex] = ζ / ( [tex]I_{cm}[/tex]+ mr²)

where [tex]\alpha[/tex] is the angular speed

[tex]\alpha[/tex] increases when the moment of inertia decreases

Therefore, it is true to say that the moment of inertia of the system decreases and the angular speed increases.