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Answer:

Weigh 4.5 grams of sodium hydroxide and add it to the dry volumetric flask of 450 mL followed by small amount of water to dissolve all the NaOH .After this add the water upto tye mark of 450 mL.

Explanation:

Molarity of the solution is the moles of compound in 1 Liter solutions.

[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}[/tex]

Mass of NaOH = x

Molar mass of NaOH = 40 g/mol

Volume of the NaOH solution =  450 mL =- 0.450 L ( 1 ml = 0.450 L)

Molarity of the solution of NaOH = 0.250 M

[tex]Molarity=\frac{1.248 g}{26 g/mol\times 0.9102254 L}=0.528 mol/L[/tex]

[tex]0.250 M=\frac{x}{40 g/mol\times 0.450 L}[/tex]

Solving for x:

x = 4.5 g

Weigh 4.5 grams of sodium hydroxide and add it to the dry volumetric flask of 450 mL followed by small amount of water to dissolve all the NaOH .After this add the water upto tye mark of 450 mL.

Eduard22sly

To prepare a 450 mL of 0.250 M NaOH solution, weigh 4.5 g of NaOH and place in a 450 mL volumetric flask. Fill the flask with water to the mark to obtain the desired solution.

How to determine the mole of NaOH

  • Molarity = 0.250 M
  • Volume = 450 mL = 450 / 1000 = 0.45 L
  • Mole of NaOH =?

Mole = Molarity x Volume

Mole of NaOH = 0.25 × 0.45

Mole of NaOH = 0.1125 mole

How to determine the mass of NaOH

  • Mole of NaOH = 0.1125 mole
  • Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
  • Mass of NaOH =?

Mass = mole × molar mass

Mass of NaOH = 0.1125 × 40

Mass of NaOH = 4.5 g

Thus, to prepare 450 mL of 0.250 M NaOH solution, 4.5 g of NaOH is needed.

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