Answer:
The test statistic value is, z = 0.57.
The p-value of the test is 0.2843.
Explanation:
A one-sided, single mean z-test can be performed to determine whether the mean caloric intake increased from 2403.7 kcal/day or not.
The hypothesis is defined as:
H₀: The mean caloric intake did not increase, i.e. μ = 2403.7.
Hₐ: The mean caloric intake did increase, i.e. μ > 2403.7.
The information provided is:
[tex]\bar x = 2453.7\ kcal/day\\n=100\\\sigma = 880\ kcal/day[/tex]
The z-statistic is:
[tex]z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}=\frac{2453.7-2403.7}{880/\sqrt{100}}=0.5682\approx0.57[/tex]
The test statistic value is, z = 0.57.
Compute the p-value of the test statistic as follows:
[tex]p-value=P(Z>0.57)=1-P(Z<0.57)=1-0.7157=0.2843[/tex]
*Use a standard normal table.
The p-value of the test is 0.2843.