Respuesta :
Answer: The volume of the balloon is [tex]4.58\times 10^3[/tex]
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas = 722 mm Hg
[tex]P_2[/tex] = final pressure of gas = 339 mm Hg
[tex]V_1[/tex] = initial volume of gas = [tex]2.88\times 10^3[/tex]
[tex]V_2[/tex] = final volume of gas = ?
[tex]T_1[/tex] = initial temperature of gas = [tex]19^oC=273+19=292K[/tex]
[tex]T_2[/tex] = final temperature of gas = [tex]-55^oC=273-55=218K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{722\times 2.88\times 10^3}{292}=\frac{339\times V_2}{218}[/tex]
[tex]V_2=4.58\times 10^3[/tex]
Thus the volume of the balloon is [tex]4.58\times 10^3[/tex]
