Answer:
[tex]1.46m/s^{2}[/tex]
Explanation:
Data
Time: [tex]t=23.4s[/tex]
Length: [tex]l=200m[/tex]
Radius: [tex]r=50m[/tex]
We need to find centripetal acceleration
Velocity is the change of distance with time according to motion equation.
therefore
velocity:
[tex]v=\frac{L}{t} \\v=\frac{200}{23.4}\\ v=8.55m/s[/tex]
The centripetal acceleration ([tex]a_{c}[/tex]) is equal to the square of the velocity, divided by the radius of the circular path.
[tex]a_{c} =\frac{v^{2} }{r} \\a_{a} =\frac{(8.55m/s)^{2} }{50m} \\a_{c} =\frac{73.10m^{2} s^{2} }{50m} \\a_{} =1.46m/s^{2}[/tex]
