Respuesta :
Answer:
484.925 grams KClO3.
Explanation:
Given 3.50 moles of KCl as the target amount in the problem, used the coefficient of the balanced chemical reaction involved to determine the number of moles of potassium perchlorate needed.
Mass of potassium perchlorate, g = 3.50 moles KCl x [(2 mol KClO3)/(2 mol KCl)] x [(138.55 g KClO3)/(1 mol KClO3)] = 484.925 grams KClO3.
The number of grams of KClO3 are needed to make 3.50 moles of KCl should be 484.925 grams KClO3.
Calculation of the number of grams:
Since there is 3.50 moles of KCl since the target amount in the problem, should be applied the coefficient of the balanced chemical reaction
Now
Mass of potassium perchlorate, g = 3.50 moles KCl x [(2 mol KClO3)/(2 mol KCl)] x [(138.55 g KClO3)/(1 mol KClO3)]
= 484.925 grams KClO3.
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