Respuesta :
The question is incomplete, here is the complete question:
The given chemical reaction is:
[tex]2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3[/tex]
What is the theoretical yield of Calcium if we begin with 12.6 grams of Aluminium?
Answer: The theoretical yield of copper is 44.48 grams
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] .....(1)
Given mass of aluminium = 12.6 g
Molar mass of aluminium = 27 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of aluminium}=\frac{12.6g}{27g/mol}=0.467mol[/tex]
The given chemical equation follows:
[tex]2Al+3Cu(NO_3)_2\rightarrow 3Cu+2Al(NO_3)_3[/tex]
By Stoichiometry of the reaction:
2 moles of aluminium produces 3 moles of copper
So, 0.467 moles of aluminium will produce = [tex]\frac{3}{2}\times 0.467=0.7005mol[/tex] of copper
Now, calculating the mass of copper from equation 1, we get:
Molar mass of copper = 63.5 g/mol
Moles of copper = 0.7005 moles
Putting values in equation 1, we get:
[tex]0.7005mol=\frac{\text{Mass of copper}}{63.5g/mol}\\\\\text{Mass of copper}=(0.7005mol\times 63.5g/mol)=44.48g[/tex]
Hence, the theoretical yield of copper is 44.48 grams
