Answer:
Net Cell Voltage = 0.28v
Explanation:
The Rxn process here is
Fe°(s) + Pb⁺²(aq) => Fe⁺²(aq) + Pb(s)
∴ Half-Rxns are:
Fe°(s) => Fe⁺²(aq) + 2e⁻ E°(Oxdn) = -0.41v*
Pb⁺²(aq) + 2e⁻ => Pb°(s) E°(Redn) = -0.13v*
Net Cell Voltage = E°(Redn) - E°(Oxdn) = (-0.13v) - (-0.41v) = 0.28v
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*From Table of Standard Cell Potentials at 25°C, 1Atm Pressure
