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1. A diffraction grating with 5.000 x 103 lines/cm is used to examine the sodium

spectrum. Calculate the angular separation of the two closely spaced yellow lines

of sodium (588.995 nm and 589.592 nm) in each of the first three orders.

Respuesta :

aabdulsamir

Answer:

0.0002°, 0.1691°, 0.338°

Explanation:

Difference between the two line = 5.97 * 10-⁸m

d = 1 / N

N = 5.0 * 10³

d = 2.0 * 10⁴m

nL = Nsin¤

For first order

588.995 * 10-⁹ = 2.0 * 10-⁴ sin ¤

Sin¤ = 2.944*10-³

¤ = sin-¹ 0.002944

¤ = 0.1687°

First order ¤ =

Sin-¹(589.592*-⁹ / 2.0 * 10-⁴)

Sin-¹ (0.002947) = 0.1689°

Angular separation = 0.1689 - 0.1687 = 0.0002°

Second order ¤ = sin-¹ [2 (589.59*10-⁹ / 2.0*10-⁴)] = sin-¹ (0.005895)

Second order ¤ = 0.3378°

Angular difference = 0.3378° - 0.1687° = 0.1691°

Third order ¤ = sin-¹ [3(589.59*10-⁹ /2.0*10-⁴] = 0.5067°

Angular difference = 0.5067° - 0.1687° = 0.338°

The angular separation for the first three orders should be 0.0002°, 0.1691°, 0.338°.

Calculation of the angular separation:

Since

Difference between the two line = 5.97 * 10-⁸m

So,

d = 1 / N

Now

N = 5.0 * 10³

d = 2.0 * 10⁴m

nL = Nsin¤

Now

For first order

588.995 * 10-⁹ = 2.0 * 10-⁴ sin ¤

Sin¤ = 2.944*10-³

¤ = sin-¹ 0.002944

¤ = 0.1687°

First-order ¤ =

Sin-¹(589.592*-⁹ / 2.0 * 10-⁴)

Sin-¹ (0.002947) = 0.1689°

Now finally

Angular separation

= 0.1689 - 0.1687

= 0.0002°

For Second order ¤

= sin-¹ [2 (589.59*10-⁹ / 2.0*10-⁴)]

= sin-¹ (0.005895)

= 0.3378°

Now

Angular difference = 0.3378° - 0.1687°

= 0.1691°

For Third order ¤

= sin-¹ [3(589.59*10-⁹ /2.0*10-⁴]

= 0.5067°

So,

Angular difference

= 0.5067° - 0.1687°

= 0.338°

hence, The angular separation for the first three orders should be 0.0002°, 0.1691°, 0.338°.

Learn more about sodium here: https://brainly.com/question/21845223

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