Respuesta :
Answers and explanations:
1. For each genotype, indicate whether it is heterozygous (A) or homozygous (B).
Homozygous (A) and heterozygous (B) refers to the presence of two equal or different alleles for the same trait, respectively.
- AA (A).
- Bb (B).
- Cc (B).
- Dd (B).
- Ee (B).
- ff (B).
- GG (A).
- HH (A).
- Jj (B).
- kk (A).
- Ll (B).
- Mm (B).
- nn (A).
- OO (A).
- Pp (B).
2. For each of the genotypes below, determine the phenotype.
A) Purple flowers are dominant to white flowers
- QQ Purple flowers.
- Qq Purple flowers.
- qq White flowers.
B) Brown eyes are dominant to blue eyes
- BB Brown eyes.
- Bb Brown eyes.
- bb Blue eyes.
C) Round seeds are dominant to wrinkled
- RR Round seeds.
- Rr Round seeds.
- rr Wrinled seeds.
D) Bobtails are recessive (long tails dominant)
TT Longtails.
Tt Longtails.
tt Bobtails.
3. For each phenotype, list the genotypes. (Use the letter of the dominant trait)
Straight hair is dominant to curly.
SS Straight.
Ss Straight.
ss Curly.
Pointed heads are dominant to round heads.
PP Pointed .
Pp Pointed .
pp Round.
4. Set up the Punnett square for each of the crosses listed below. The trait being studied is round seeds (dominant) and wrinkled seeds (recessive).
A) Rr x rr
Alelles R r
r Rr rr
r Rr rr
Results of the crossing
- RR (Round seed homozygous) None.
- Rr (Round seed heterozygous) 50%.
- rr (Wrinkled seeds homozygous) 50%.
What percentage of the offspring will be round?
- 50%
B) Rr x Rr
Alelles R r
R RR Rr
r Rr rr
Results of the crossing
- RR (Round seed homozygous) 25%.
- Rr (Round seed heterozygous) 50%.
- rr (Wrinkled seeds homozygous) 25%.
What percentage of the offspring will be round?
- 75 %
C) RR x Rr
Alelles R R
R RR RR
r Rr Rr
Results of the crossing
- RR (Round seed homozygous) 50%.
- Rr (Round seed heterozygous) 50%.
- rr (Wrinkled seeds homozygous) None.
What percentage of the offspring will be round?
- 100%
5. Punnett squares.
A) A TT (tall) plant is crossed with a tt (short plant). What percentage of the offspring will be tall?
The result of the cross between two pure lines (TT and tt) is always a 100% heterozygous offspring (Tt), with the phenotype of the dominant trait.
Alelles T T
t Tt Tt
t Tt Tt
100% of the offspring will be tall.
B) Tt X Tt
Alelles T t
T TT Tt
t Tt tt
Results of the crossing
- TT (Tall plants homozygous) 25%.
- Tt (Tall plants heterozygous) 50%.
- tt (Short plants homozygous) 25%.
25% of the offspring will be short.
C) RR X Rr
Alelles R R
R RR RR
r Rr Rr
Results of the crossing
- RR (Round seed homozygous) 50%.
- Rr (Round seed heterozygous) 50%.
- rr (Wrinkled seeds homozygous) None.
50% of the offspring will be homozygous (RR).
D) RR X rr
Parent Genotypes: Homozygous round seeded RR and homozygous wrinkled seed rr.
Alelles R R
r Rr Rr
r Rr Rr
There are no homozygous offspring at this crossing.
E) White/Yellow flowered (pea) plants.
Q for yellow flowers.
q for white flowers.
Parent Genotypes: Pea plants white flowers qq.
Alelles q q
q qq qq
q qq qq
100% of the offspring will be white flowered (qq).
F) White/Yellow flowered plants.
- Q for yellow flowers.
- q for white flowers.
Parent Genotypes: White flowered plant qq and yellow flowered plant (heterozygous) Qq.
Alelles Q q
q Qq qq
q Qq qq
Results of the crossing
- QQ (Yellow flowered homozygous) none
- Qq (Yellow flowered heterozygous) 50%.
- qq (White flowered homozygous) 50%.
50% of the offspring will be yellow flowered (Qq).
G) Qq X Qq
Parent Genotypes: Yellow flowered plant Qq (both heterozygous).
Alelles Q q
Q QQ Qq
q Qq qq
Results of the crossing
- QQ (Yellow flowered homozygous) 25%.
- Qq (Yellow flowered heterozygous) 50%.
- qq (White flowered homozygous) 25%.
75% of the offspring will have yellow flowers (QQ and Qq).
25% of the offspring will have white flowers (qq).
H) Guinea pigs, the allele for long hair is dominant.
C for longhaired guinea pig.
c for shorthaired guinea pig.
- Heterozygous longhaired guinea pig have Cc genotype.
- Pure breeding longhaired guinea pig have CC genotype.
- Shorthaired guinea pig have cc genotype.
I) Guinea pigs CC X cc
Parent Genotypes:
- Pure breeding longhaired guinea pig have CC genotype.
- Shorthaired guinea pig have cc genotype.
CC X cc
Alelles C C
c Cc Cc
c Cc Cc
100% of the offspring will have long hair (Cc)
J) Guinea pigs Cc X Cc
Alelles C c
C CC Cc
c Cc cc
Results of the crossing
- CC (Long hair homozygous) 25%.
- Qq (Long hair heterozygous) 50%.
- qq (Short hair homozygous) 25%.