Respuesta :
Answer: tea = 15 rupees per kg
sugar= 3 rupees per kg
Step-by-step explanation:
Hi, to answer this question we have to write a system of equations with the information given:
"Two kg of tea and 3 kg of sugar cost rupees 39 in january 1997":
2 t + 3 s =39 (a)
Where:
- t= price of 1 kg of tea
- s = price of 1 kg of sugar
"in march 1997 the price of the tea increased by 25% (1.25)and the price of the sugar increased by 20%(1.20) and the same quantity of tea and sugar cost rupees 48.30. "
2(t1.25)+3(s1.2) = 48.30 (b)
- Solving for t in (b)
2t =39-3s
t = (39 -3s)/2
t = 19.5-1.5s
- Replacing the value of t in (b)
2 x ((19.5-1.5s)1.25)+ 3 ( 1.2s) =48.30
2x ( 24.375 -1.875s) +3.6s =48.30
48.75 -3.75s+3.6s= 48.30
48.75-48.30 = 3.75s-3.6s
0.45= 0.15s
0.45/0.15 =s
3 =s
- Replacing the value of s in (a)
2 t + 3 (3) =39
2 t + 9 =39
2 t =39 -9
2 t =30
t = 30/2
t= 15
Prices in january:
tea = 15 rupees per kg
sugar= 3 rupees per kg
Feel free to ask for more if needed or if you did not understand something.
Answer:
x = 15 rupees by kg ( price of tea)
y = 3 rupees by kg ( price of sugar)
Step-by-step explanation:
Let call " x " the price of kg of tea and " y " the price of kg of sugar, in january of 1997,
then according to problem statement
2*x + 3*y = 39 (1)
But in march prices increased
tea by 25% that means its price in march will be 1.25*x, and the price of sugar will be 1.20*y, finally buying the same quantities now cost 48.30 rupees, then
2* ( 1.25*x ) + 3 * ( 1.20*y) = 48.30
2,50*x + 3.60*y = 48.30 (2)
Equations (1) and (2) are a two equation system, we need to solve for x and y
From equation (1) we have y = ( 39 - 2*x ) / 3
Plugging that value in equation (2)
2,50*x + 3.60* [ ( 39 - 2*x ) / 3] = 48.30
2,50*x + ( 140,40 - 7,20*x ) /3 = 48.30
7.50*x + 140,40 - 7,20*x = 144,90
0,30*x = 4.50
x = 4.50/0.30
x = 15 rupees
and y = ( 39 - 2*x ) / 3 ⇒ y = ( 39 - 2*15 ) / 3
y = ( 39 - 30 )/3
y = 3 rupees
