AshNo
contestada

60 points & Brainliest! (Please show all steps)


g(x) = (x + 2)(x - 1)(x - 2)

a1) Find the zeros of the function.
a2) Show How you found the Zeros

b1) Find the y-intercept of the function.
b2) Show your work

c) Create the graph of the polynomial.
D) Describe the end behavior of the graph.

Respuesta :

Zeros:
You get the zeros through the zero product property so

X+2=0. X-1=0. X-2=0. So your zeros are
-2, 1, and 2.

Y intercept:

To find your y intercept just substitute 0 for x
G(0)=(0+2)(0-1)(0-2) and your y int is 4.

Graphing:

To graph it Plot your zeros first at the right coordinates. So (-2,0), (1,0), and (2,0) since the degree of the zeros are odd the line goes through the coordinates.

Once you get this you have to see how your graphs moves on the left and right.

So you essentially substitute -∞ and ∞ for your x.

Left of graph
G(-∞)= (-)(-)(-) and since you have three negative values your y will also be negatives so it goes down on the left.
Right of graph
G(∞)=(+)(+)(+) since this has three positives values your y will be positive so it goes up on right.

Answer:

See below .

Step-by-step explanation:

This is a cubic function whose graph will contain 2 loops.

a)  (x + 2)(x - 1)(x - 2) = 0

Since this a product of 3 terms and the result is zero all 3 could be  zero so we have:

x + 2 = 0, x - 1 = 0 or x - 2 = 0

So the zeroes are -2, 1 and 2.

b) the y -intercept occurs when x = 0 , so substituting for x:

y-intercept =   (0 + 2)(0 - 1)(0 - 2) = 2*-1*-2 =  4 = y coordinate of the y-intercept

y-intercept  is at (0, 4).

c)  Plot the points  (-2, 0), ( 1, 0), ( 2, 0) and (0, 4).

Also I suggest you  you plot  some points (-1, 6) and  (1.5 , -0.9) where the graph will  have loops.

d) As the leading coefficient  is positive  the graph will fall to the left and rise to the right.

Otras preguntas