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A 52.9g sample of brass, which has a specific heat capacity of 0.375·J·g−1°C−1, is put into a calorimeter (see sketch at right) that contains 100.0g of water. The temperature of the water starts off at 15.0°C. When the temperature of the water stops changing it's 18.4°C. The pressure remains constant at 1 atm. Calculate the initial temperature of the brass sample. Be sure your answer is rounded to 2 significant digits.

Respuesta :

drpelezo

Answer:

T₁ = 90°C

Explanation:

Let system 1 => brass sample & system 2 => water

∑q = 0 = q₁ + q₂ =  (mcΔT)₁ + (mcΔT)₂

= [(52.9g)(0.375j/g°C)(18.4°C - T₁)]₁ + [(100.0g)(4.184j/g°C)(18.4°C - 15°C)]₂ = 0

=> 19.83(18.4°C - T₁) + 1423 = 0 => 365 - 19.83T₁ + 1423 = 0

=>19.83T₁ = 1788 => T₁ = (1788/19.83)°C = 90°C

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