Respuesta :
Answer:
Internal resistance for cell p is [tex]9 ohm[/tex].
Explanation:
From the Question,
Emf of cell p & q are [tex]1.5v[/tex] and [tex]2.0v[/tex] respectively. Internal resistance of cell q is [tex]1ohm[/tex].
Current reads by ammeter is [tex]50mA[/tex].
So, According to question
Applying Ohm's law
[tex]V = IR[/tex]
Where I - Current
V- Voltage
And R- Resistance
then,
[tex]I = \frac{V}{R}[/tex]
[tex]50mA = \frac{2-1.5}{R+1}[/tex]
[tex]R+1 = \frac{0.5}{0.05}[/tex] {∵ [tex]50 mA = 50\times10^{-3} A[/tex]}
[tex]R = 10 - 1[/tex]
[tex]R = 9 ohm[/tex]
Therefore , Internal resistance for cell P is 9 ohm.
