Answer:
The electrical energy supplied is 0.233 kWh
Explanation:
Given :
Mass of air [tex]m = 15[/tex] kg
Initial temperature [tex]T _{1} =[/tex] 298 K
Final temperature [tex]T_{2} =[/tex] 350 K
Heat loss [tex]Q _{out} = 60[/tex] kJ
From the first law of thermodynamics,
[tex]\Delta U = W_{in} - W_{out} - Q_{out}[/tex]
We know that internal energy is proportional to difference of temperature,
[tex]W_{in} = m (T_{2} - T_{1} ) + 60[/tex]
[tex]W_{in} = 15 \times (350-298) + 60 }[/tex]
Now we need answer into kWh so ( 1 kWh = 3600 kJ ).
So we need to multiply ( [tex]\frac{1}{3600}[/tex] )
[tex]W_{in} = [15 \times (350-298) + 60 ] \times \frac{1}{3600}[/tex] kWh
[tex]W_{in} = 0.233[/tex] kWh
Therefore, the electrical energy supplied 0.233 kWh
