Answer:
145 ° C
Explanation:
Using the expression
[tex]V_{rms} = \sqrt{\frac{3RT}{M} }[/tex]
where T = 17 ° C = (273 + 17) K
= 290 K
[tex]V_{rms} = 1.2[/tex]
So; At what temperature will its root-mean-square speed (thermal speed) be 1.2 times its value at 17.0 deg C?
What this implies is that:
[tex]\sqrt{\frac{3RT}{M} }= 1.2 \sqrt{\frac{3*R*290}{M} }[/tex] where R & M are constant
T = 144.6 ° C
T = 145 ° C
