Answer:
So heat required to raise the temperature of water is given as Q = 33472 J
Explanation:
As we know that the temperature of water is increased by 2 Degree C
So here we have heat gain by the water is given by the equation
[tex]Q = m s\Delta T[/tex]
Now we know that
m = 1000 g
s = 4.184 J/g C
Now plug in all data in above equation
[tex]Q = 1000(4.184)(2)[/tex]
[tex]Q = 33472 J[/tex]
The amount of energy flow from the higher temperature to lower temperature, is known as heat energy.
The amount of heat energy gained by the water is of 33472 J.
Given Data:
The mass of Aluminum is, m = 125 g = 0.125 kg.
The mass of water is, m ' = 1000 g = 1 kg.
The temperature change of water is, ΔT = 2°C.
The heat capacity of water is, c = 4.184 J/g°C.
Since the temperature of water is increased by 2°C. And the temperature increase signifies that there must be some heat gain took place.
So, the expression for the heat gain by the water is given as,
Q = m' × c × ΔT
Solving as,
Q = 1000 × 4.184 × 2
Q = 33472 J
Thus, we can conclude that the amount of heat energy gained by the water is of 33472 J.
Learn more about the heat gain here:
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