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A discount store is selling 5 small tables with 8 chairs for $115. Three tables with 5 chairs cost $70.

1)
Which system of linear equations could be used to find the cost of each table (x) and the cost of each chair (y)?
A) 3x + 8y = $70; 8x + 3y = $115
B) 5x + 8y = $115; 3x + 5y = $70
C) 5x + 8y = $115; 2x − 5y = $70
D) 8x + 5y = $115; 5x + 3y = $70

2)
Determine the cost of each table (x) and the cost of each chair (y).
A) x = $15; y = $5
B) x = $10; y = $5
Eliminate
C) x = $5; y = $10
D) x = $12; y = $3

Respuesta :

The system of linear equations are 5x+8y = 115 and 3x+5y = 70.

The cost of each table (x) is $15 and cost of each chair is $5.

What is system of linear equations?

"A system of linear equations is a collection of one or more linear equations involving the same set of variables. For example, is a system of three equations in the three variables x, y, z."

Let x be the cost of each table and y be the cost of each chair

According to the question,

Five small tables with eight chairs cost $115

We can write an equation

5x+8y = 115..................(1)

Next, three small tables and five chairs cost $70

we can write an equation

3x+5y = 70...................(2)

We have two equations and two unknowns (x and y)

Solving 5x+8y = 115

⇒ [tex]x = \frac{(115-8y)}{5}[/tex]

Substitute x in equation (2)

⇒ [tex]3.\frac{(115-8y)}{5} +5y = 70[/tex]

⇒ [tex]3.\frac{115}{5}-\frac{3.8}{5} y+5y = 70[/tex]

⇒ [tex]69-\frac{24}{5}y+5y = 70[/tex]

⇒ [tex]\frac{(-24y+25y)}{5} = 70-69[/tex]

⇒ [tex]\frac{1}{5}.y = 1[/tex]

⇒ y = $5

Substitute y = $5 in x

⇒ [tex]x = \frac{(115-8y)}{5}[/tex]

⇒ [tex]x = \frac{(115-8(5))}{5}[/tex]

⇒ x = $15

Hence, the system of linear equations are 5x+8y = 115 and 3x+5y = 70

The cost of each table (x) is $15 and cost of each chair is $5.

Learn more about system of linear equations here

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