Answer:
The concentration of 2-phosphoglycerate = 0.344 mM
Explanation:
ΔG° for the conversion of 3-phosphoglycerate to 2-phosphoglycerate (2PG) is + 4.40 kJ/mole.
We know ΔG° = [tex]- 2.303 RTlogK[/tex]
where R = Universal gas constant = 8.314 x 10⁻³ kj.mole⁻¹. k⁻¹
T = Kelvin temperature = 25 + 273 = 298 K
⇒ log K = [tex]\frac{4.4}{-2.303X8.314X10^{-3}X298 }[/tex]
⇒ log K = - 0.77
⇒ K = 0.16
3-phosphoglycerate → 2-phosphoglycerate
[tex]K = \frac{[2 - phosphogycerate]}{[3-phosphoglycerate]}[/tex]
Where 'K' is equilibrium constant
[tex]0.16=\frac{x}{2.15X10^{-3} }[/tex]
⇒ x = 0.16 x 2.15 x 10⁻³
⇒ x = 0.000344 molar or 0.344 mM at 25°C
