Answer: Thus the solubility of [tex]N_2[/tex] gas in water, at the same temperature, if the partial pressure of gas is 10.0 atm is 235mg/100g.
Explanation:-
The Solubility of [tex]N_{2}[/tex] in water can be calculated by Henry’s Law. Henry’s law gives the relation between gas pressure and the concentration of dissolved gas.
Formula of Henry’s law, [tex]C=k_{H}P[/tex].
[tex]k_{H}[/tex]= Henry’s law constant = ?
The partial pressure (P) of [tex]N_{2}[/tex] in water = 4.07 atm
\[tex]C= k_{H}\times P\\95.7mg=k_{H}\times 4.07[/tex]
[tex]k_{H}=23.5[/tex]
At pressure of 10.0 atm
[tex]C= k_{H}\times P\\C=23.5\times 10.0=235mg/100mg[/tex]
Thus the solubility of [tex]N_2[/tex] gas in water, at the same temperature, is 235mg/100g
