Answer:
The angular magnification is [tex]M = 2.808[/tex]
Explanation:
From the question we are told
The focal length is [tex]f = 8.9cm[/tex]
The near point is [tex]n_p = 25.0cm[/tex]
The angular magnification is mathematically represented as
[tex]M = \frac{n_p}{f}[/tex]
Substituting values
[tex]M = \frac{25}{8.9}[/tex]
[tex]= 2.808[/tex]