Respuesta :
The net gravitational force on the center object due to the other two is 0.
Newton's law of gravitation is given by:
F = Gm₁m₂/r²
Where F is the force, m₁, m₂ are masses, r is the distance between the two masses and G is the gravitational constant = 6.67 * 10⁻¹¹ Nm²/kg²
Given that m₁ = m₂ = 10 kg, r = 50 cm = 0.5 m, hence:
F(to the right object) = 6.67 * 10⁻¹¹ Nm²/kg² * 10 kg * 10 kg / 0.5²
F = 2.668 * 10⁻⁸ N
F(to the left object) = -6.67 * 10⁻¹¹ Nm²/kg² * 10 kg * 10 kg / 0.5²
F = -2.668 * 10⁻⁸ N
Net gravitational force = 2.668 * 10⁻⁸ N + (-2.668 * 10⁻⁸ N) = 0
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