contestada

Three objects each with a mass of 10.0 kg are
placed in a straight line 50.0 cm apart. What is the
net gravitational force on the center object due to
the other two?

Respuesta :

Answer: F net=0

Explanation:

Its in the picture.

Ver imagen paulaboo

The  net gravitational force on the center object due to  the other two is 0.

Newton's law of gravitation is given by:

F = Gm₁m₂/r²

Where F is the force, m₁, m₂ are masses, r is the distance between the two masses and G is the gravitational constant = 6.67 * 10⁻¹¹ Nm²/kg²

Given that m₁ = m₂ = 10 kg, r = 50 cm = 0.5 m, hence:

F(to the right object) = 6.67 * 10⁻¹¹ Nm²/kg² * 10 kg * 10 kg / 0.5²

F = 2.668 * 10⁻⁸ N

F(to the left object) = -6.67 * 10⁻¹¹ Nm²/kg² * 10 kg * 10 kg / 0.5²

F = -2.668 * 10⁻⁸ N

Net gravitational force = 2.668 * 10⁻⁸ N + (-2.668 * 10⁻⁸ N) = 0

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