Answer:
F= 1.334x10^-8N
Explanation:.
F(AB)=100G/(50x10^-2)^2
F(CB)=150G/(50x10^-2)^2
F(net)=F(AB)-F(CB)
Note that, distance should be in meters so convert it into meter or directly use its meter value (50x10^-2m)
Substitude the value of G=6.67x10^-11Nm^2/kg^2 into the equations and the do the calculations you will obtain the answer.
The net force on B due to A and C will be "1.33 × 10⁻⁸ N". To understand the calculation, check below.
According to the question,
Mass of A and B = 10.0 kg
Mass of C = 15.0 kg
Radius, r₁ = r₂ = r = 50.0 cm or,
= 0.5 m
We know, G = 6.67 × 10⁻¹¹ m³/kg.s²
According to the formula,
→ [tex]F_{BC}[/tex] = [tex]\frac{G M_B M_C}{r_1^2}[/tex]
or,
→ [tex]F_{AB} = \frac{G M_A M_B}{r_1^2}[/tex]
The net force be:
→ [tex]F_{Net}[/tex] = [tex]F_{BC} - F_{AB}[/tex]
= [tex]\frac{G M_B M_C}{r^2} - \frac{D M_A M_B}{r^2}[/tex]
= [tex]\frac{G M_B}{r^2}[/tex] [[tex]M_C -M_A[/tex]]
By substituting the values,
= [tex]\frac{6.674\times 10^{-11}\times 10}{(0.5)^2}[/tex] [15 - 10]
= 1334.8 × 10⁻¹¹ N or,
= 1.33 × 10⁻⁸ N
Thus the above response is correct.
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