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The simple 3.4-kg pendulum is released from rest in the horizontal position. As it reaches the bottom position, the cord wraps around the smooth fixed pin at B and continues in the smaller arc in the vertical plane. Calculate the magnitude of the force R supported by the pin at B when the pendulum passes the position θ = 58°.

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akande212

Answer:

R = 27.4N

Explanation:

The reaction force supported by the pin at B is an horizontally acting force. This force is equal but opposite in direction to the restoring force. The restoring force acts to the left tangential to the arc while this reaction acts to the right.

Given m= 3.4kg, θ = 58°, g = 9.8m/s

R = mgSinθ = 3.4×9.8×sin58°

R = 27.4N

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