Answer:
Voltage in the primary winding of the coil is 3.9 V
Explanation:
As we know by the principle of transformer we have
[tex]\frac{V_s}{V_p} = \frac{N_s}{N_p}[/tex]
here we know that
[tex]V_s = 25 volts[/tex]
[tex]N_s = 3200[/tex]
[tex]N_p = 500[/tex]
now we have
[tex]\frac{25}{V_p} = \frac{3200}{500}[/tex]
[tex]V_p = 3.9 Volts[/tex]