Answer:
The [tex]pK_a[/tex] of acetic acid is 4.7.
The [tex]pK_b[/tex] of methylamine is 3.4.
Explanation:
1) The dissociation constant of acetic acid = [tex]K_a=1.8\times 10^{-5}[/tex]
The [tex]pK_a[/tex] is negative logarithm of dissociation constant.
[tex]pK_a=-\log[K_a][/tex]
[tex]pK_a=-\log[1.8\times 10^{-5}]=4.7[/tex]
The [tex]pK_a[/tex] of acetic acid is 4.7.
2) The dissociation constant of methylamine = [tex]K_b=4.2\times 10^{-4}[/tex]
The [tex]pK_b[/tex] is negative logarithm of dissociation constant.
[tex]pK_b=-\log[K_b][/tex]
[tex]pK_b=-\log[4.2\times 10^{-4}]=3.4[/tex]
The [tex]pK_b[/tex] of methylamine is 3.4.
