arlene is to walk across a high wire strung horizontally between two buildings 10.0m apart. The sag in the rope when she is at the midpoint is 10.0 degrees, if her mass is 50.0 kg, what is the tension in the rope at this point?...can you help me...thanks!

we are given with a force in the middle of a rope measuring 10 m and an angle of sagging of 10 degrees from the horizontal. The tension of the rope is equal to the hypotenuse of the right triangle.

sin 10 = 50 kg * 9.8 m/s2 / T
Tension = 2821. 80 N

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aristocles aristocles · Answer 2 · 2019-09-26T02:35:26+02:00

Answer:

[tex]T = 1412.3 N[/tex]

Explanation:

As we know that weight of the Arlene is counterbalanced by the tension in the string

So here it is given that string makes 10 degree angle at mid point

So we will have

[tex]T sin\theta + T sin\theta = mg[/tex]

so we have

[tex]T = \frac{mg}{2sin\theta}[/tex]

here we know that

[tex]m = 50 kg[/tex]

[tex]\theta = 10 degree[/tex]

now we have

[tex]T = \frac{50 \times 9.81}{2sin10}[/tex]

[tex]T = 1412.3 N[/tex]