select all of the roots of x3 2x2 – 16x– 32. –1 –2 –4 1 4 5

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calculista calculista · Answer 1 · 2018-11-16T17:41:32+01:00

In order to find the roots of the cubic equations by graphing you have to follow those steps

we have

[tex]x^3+2x^2-16x-32[/tex]

we know that

The roots of the function are the values of x when the value of the function is equal to zero

Using a graphing tool

see the attached figure

The roots are

[tex]x=-4\ x=-2\ x=4[/tex]

therefore

the answer is

[tex]x=-4\ x=-2\ x=4[/tex]

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isyllus isyllus · Answer 2 · 2019-04-07T16:58:43+02:00

Answer:

The roots are -2,-4 and 4

B, C and E are correct.

Step-by-step explanation:

Given: [tex]x^3+2x^2-16x-32[/tex]

We are given a cubic polynomial. We have to find the roots of the polynomial. Roots are the x-intercept of polynomial.

First we will set the polynomial to 0 and solve for x

[tex]x^3+2x^2-16x-32=0[/tex]

[tex]x^2(x+2)-16(x+2)=0[/tex]

[tex](x+2)(x^2-16)=0[/tex]

[tex](x+2)(x+4)(x-4)=0[/tex] [tex]\because a^2-b^2=(a+b)(a-b)[/tex]

Now, we will set each factor to zero and solve for x

[tex]x+2=0\ \ \ \ x+4=0\ \ \ \ \ \ \ x-4=0[/tex]

[tex]x=-2,-4,4[/tex]

Hence, The roots are -2,-4 and 4